Solve l^542-1-1 - ScanMath

Question

Simplify the expression

42 l^{5} - 2

Evaluate

l^{5} \times 42 - 1 - 1

Use the commutative property to reorder the terms

42 l^{5} - 1 - 1

Solution

42 l^{5} - 2

Show Solution

2 (21 l^{5} - 1)

Evaluate

l^{5} \times 42 - 1 - 1

Use the commutative property to reorder the terms

42 l^{5} - 1 - 1

Subtract the numbers

42 l^{5} - 2

Solution

2 (21 l^{5} - 1)

Show Solution

l = \frac{5 2 1 ^{4}}{21}

Alternative Form

l \approx 0.543946

Evaluate

l^{5} \times 42 - 1 - 1

To find the roots of the expression,set the expression equal to 0

l^{5} \times 42 - 1 - 1 = 0

Use the commutative property to reorder the terms

42 l^{5} - 1 - 1 = 0

Subtract the numbers

42 l^{5} - 2 = 0

Move the constant to the right-hand side and change its sign

42 l^{5} = 0 + 2

Removing 0 doesn't change the value,so remove it from the expression

42 l^{5} = 2

Divide both sides

\frac{42 l ^{5}}{42} = \frac{2}{42}

Divide the numbers

l^{5} = \frac{2}{42}

Cancel out the common factor 2

l^{5} = \frac{1}{21}

Take the 5 -th root on both sides of the equation

5 l^{5} = 5 \frac{1}{21}

Calculate

l = 5 \frac{1}{21}

Solution

More Steps

Evaluate

5 \frac{1}{21}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{5 1}{5 21}

Simplify the radical expression

\frac{1}{5 21}

Multiply by the Conjugate

\frac{5 2 1 ^{4}}{5 21 \times 5 2 1 ^{4}}

Multiply the numbers

More Steps

Evaluate

521 \times 5 2 1^{4}

The product of roots with the same index is equal to the root of the product

5 21 \times 2 1^{4}

Calculate the product

5 2 1^{5}

Reduce the index of the radical and exponent with 5

21

\frac{5 2 1 ^{4}}{21}

l = \frac{5 2 1 ^{4}}{21}

Alternative Form

l \approx 0.543946

Show Solution