Question
λ=ωc
Function
Find the first partial derivative with respect to c
Find the first partial derivative with respect to ω
∂c∂λ=ω1
Simplify
λ=ωc
Find the first partial derivative by treating the variable ω as a constant and differentiating with respect to c
∂c∂λ=∂c∂(ωc)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂c∂λ=ω2∂c∂(c)ω−c×∂c∂(ω)
Use ∂x∂xn=nxn−1 to find derivative
∂c∂λ=ω21×ω−c×∂c∂(ω)
Use ∂x∂(c)=0 to find derivative
∂c∂λ=ω21×ω−c×0
Any expression multiplied by 1 remains the same
∂c∂λ=ω2ω−c×0
Any expression multiplied by 0 equals 0
∂c∂λ=ω2ω−0
Removing 0 doesn't change the value,so remove it from the expression
∂c∂λ=ω2ω
Solution
More Steps

Evaluate
ω2ω
Use the product rule aman=an−m to simplify the expression
ω2−11
Reduce the fraction
ω1
∂c∂λ=ω1
Show Solution

Solve the equation
Solve for ω
Solve for c
ω=λc
Evaluate
λ=ωc
Swap the sides of the equation
ωc=λ
Cross multiply
c=ωλ
Simplify the equation
c=λω
Swap the sides of the equation
λω=c
Divide both sides
λλω=λc
Solution
ω=λc
Show Solution
