Solve lambda=4l/n

Evaluate

λ = 4 \times \frac{l}{n}

Simplify

λ = \frac{4 l}{n}

Find the first partial derivative by treating the variable n as a constant and differentiating with respect to l

\frac{\partial λ}{\partial l} = \frac{\partial}{\partial l} (\frac{4 l}{n})

Use differentiation rule \frac{\partial}{\partial x} (\frac{f ( x )}{g ( x )}) = \frac{\frac{\partial}{\partial x} ( f ( x )) \times g ( x ) - f ( x ) \times \frac{\partial}{\partial x} ( g ( x ) )}{( g ( x ) ) ^{2}}

\frac{\partial λ}{\partial l} = \frac{\frac{\partial}{\partial l} ( 4 l ) n - 4 l \times \frac{\partial}{\partial l} ( n )}{n ^{2}}

Evaluate

More Steps

\frac{\partial λ}{\partial l} = \frac{4 n - 4 l \times \frac{\partial}{\partial l} ( n )}{n ^{2}}

Use \frac{\partial}{\partial x} (c) = 0 to find derivative

\frac{\partial λ}{\partial l} = \frac{4 n - 4 l \times 0}{n ^{2}}

Any expression multiplied by 0 equals 0

\frac{\partial λ}{\partial l} = \frac{4 n - 0}{n ^{2}}

Removing 0 doesn't change the value,so remove it from the expression

\frac{\partial λ}{\partial l} = \frac{4 n}{n ^{2}}

Solution

More Steps

\frac{\partial λ}{\partial l} = \frac{4}{n}

Function