Solve log2(3-x)>3

Evaluate

lo g_{10} (2) \times (3 - x) > 3

Divide both sides

\frac{lo g _{10} ( 2 ) \times ( 3 - x )}{lo g _{10} ( 2 )} > \frac{3}{lo g _{10} ( 2 )}

Divide the numbers

3 - x > \frac{3}{lo g _{10} ( 2 )}

Move the constant to the right side

- x > \frac{3}{lo g _{10} ( 2 )} - 3

Subtract the numbers

More Steps

- x > lo g_{2} (125)

Change the signs on both sides of the inequality and flip the inequality sign

x < - lo g_{2} (125)

Solution

More Steps

x < - 3 lo g_{2} (5)

Alternative Form

x \in (- \infty, - 3 lo g_{2} (5))

Solve the inequality