Solve m^25988/1-168

Question

Simplify the expression

5988 m^{2} - 168

Evaluate

m^{2} \times \frac{5988}{1} - 168

Divide the terms

m^{2} \times 5988 - 168

Solution

5988 m^{2} - 168

Show Solution

12 (499 m^{2} - 14)

Evaluate

m^{2} \times \frac{5988}{1} - 168

Divide the terms

m^{2} \times 5988 - 168

Use the commutative property to reorder the terms

5988 m^{2} - 168

Solution

12 (499 m^{2} - 14)

Show Solution

m_{1} = - \frac{6986}{499}, m_{2} = \frac{6986}{499}

Alternative Form

m_{1} \approx - 0.1675, m_{2} \approx 0.1675

Evaluate

m^{2} \times \frac{5988}{1} - 168

To find the roots of the expression,set the expression equal to 0

m^{2} \times \frac{5988}{1} - 168 = 0

Divide the terms

m^{2} \times 5988 - 168 = 0

Use the commutative property to reorder the terms

5988 m^{2} - 168 = 0

Move the constant to the right-hand side and change its sign

5988 m^{2} = 0 + 168

Removing 0 doesn't change the value,so remove it from the expression

5988 m^{2} = 168

Divide both sides

\frac{5988 m ^{2}}{5988} = \frac{168}{5988}

Divide the numbers

m^{2} = \frac{168}{5988}

Cancel out the common factor 12

m^{2} = \frac{14}{499}

Take the root of both sides of the equation and remember to use both positive and negative roots

m = \pm \frac{14}{499}

Simplify the expression

More Steps

Evaluate

\frac{14}{499}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{14}{499}

Multiply by the Conjugate

\frac{14 \times 499}{499 \times 499}

Multiply the numbers

More Steps

Evaluate

14 \times 499

The product of roots with the same index is equal to the root of the product

14 \times 499

Calculate the product

6986

\frac{6986}{499 \times 499}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{6986}{499}

m = \pm \frac{6986}{499}

Separate the equation into 2 possible cases

m = \frac{6986}{499} m = - \frac{6986}{499}

Solution

m_{1} = - \frac{6986}{499}, m_{2} = \frac{6986}{499}

Alternative Form

m_{1} \approx - 0.1675, m_{2} \approx 0.1675

Show Solution