Solve m^25988/1-16

Question

Simplify the expression

5988 m^{2} - 16

Evaluate

m^{2} \times \frac{5988}{1} - 16

Divide the terms

m^{2} \times 5988 - 16

Solution

5988 m^{2} - 16

Show Solution

4 (1497 m^{2} - 4)

Evaluate

m^{2} \times \frac{5988}{1} - 16

Divide the terms

m^{2} \times 5988 - 16

Use the commutative property to reorder the terms

5988 m^{2} - 16

Solution

4 (1497 m^{2} - 4)

Show Solution

m_{1} = - \frac{2 1497}{1497}, m_{2} = \frac{2 1497}{1497}

Alternative Form

m_{1} \approx - 0.051691, m_{2} \approx 0.051691

Evaluate

m^{2} \times \frac{5988}{1} - 16

To find the roots of the expression,set the expression equal to 0

m^{2} \times \frac{5988}{1} - 16 = 0

Divide the terms

m^{2} \times 5988 - 16 = 0

Use the commutative property to reorder the terms

5988 m^{2} - 16 = 0

Move the constant to the right-hand side and change its sign

5988 m^{2} = 0 + 16

Removing 0 doesn't change the value,so remove it from the expression

5988 m^{2} = 16

Divide both sides

\frac{5988 m ^{2}}{5988} = \frac{16}{5988}

Divide the numbers

m^{2} = \frac{16}{5988}

Cancel out the common factor 4

m^{2} = \frac{4}{1497}

Take the root of both sides of the equation and remember to use both positive and negative roots

m = \pm \frac{4}{1497}

Simplify the expression

More Steps

Evaluate

\frac{4}{1497}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{4}{1497}

Simplify the radical expression

More Steps

Evaluate

4

Write the number in exponential form with the base of 2

2^{2}

Reduce the index of the radical and exponent with 2

2

\frac{2}{1497}

Multiply by the Conjugate

\frac{2 1497}{1497 \times 1497}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{2 1497}{1497}

m = \pm \frac{2 1497}{1497}

Separate the equation into 2 possible cases

m = \frac{2 1497}{1497} m = - \frac{2 1497}{1497}

Solution

m_{1} = - \frac{2 1497}{1497}, m_{2} = \frac{2 1497}{1497}

Alternative Form

m_{1} \approx - 0.051691, m_{2} \approx 0.051691

Show Solution