Solve m^25988/1-212

Question

Simplify the expression

5988 m^{2} - 212

Evaluate

m^{2} \times \frac{5988}{1} - 212

Divide the terms

m^{2} \times 5988 - 212

Solution

5988 m^{2} - 212

Show Solution

4 (1497 m^{2} - 53)

Evaluate

m^{2} \times \frac{5988}{1} - 212

Divide the terms

m^{2} \times 5988 - 212

Use the commutative property to reorder the terms

5988 m^{2} - 212

Solution

4 (1497 m^{2} - 53)

Show Solution

m_{1} = - \frac{79341}{1497}, m_{2} = \frac{79341}{1497}

Alternative Form

m_{1} \approx - 0.18816, m_{2} \approx 0.18816

Evaluate

m^{2} \times \frac{5988}{1} - 212

To find the roots of the expression,set the expression equal to 0

m^{2} \times \frac{5988}{1} - 212 = 0

Divide the terms

m^{2} \times 5988 - 212 = 0

Use the commutative property to reorder the terms

5988 m^{2} - 212 = 0

Move the constant to the right-hand side and change its sign

5988 m^{2} = 0 + 212

Removing 0 doesn't change the value,so remove it from the expression

5988 m^{2} = 212

Divide both sides

\frac{5988 m ^{2}}{5988} = \frac{212}{5988}

Divide the numbers

m^{2} = \frac{212}{5988}

Cancel out the common factor 4

m^{2} = \frac{53}{1497}

Take the root of both sides of the equation and remember to use both positive and negative roots

m = \pm \frac{53}{1497}

Simplify the expression

More Steps

Evaluate

\frac{53}{1497}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{53}{1497}

Multiply by the Conjugate

\frac{53 \times 1497}{1497 \times 1497}

Multiply the numbers

More Steps

Evaluate

53 \times 1497

The product of roots with the same index is equal to the root of the product

53 \times 1497

Calculate the product

79341

\frac{79341}{1497 \times 1497}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{79341}{1497}

m = \pm \frac{79341}{1497}

Separate the equation into 2 possible cases

m = \frac{79341}{1497} m = - \frac{79341}{1497}

Solution

m_{1} = - \frac{79341}{1497}, m_{2} = \frac{79341}{1497}

Alternative Form

m_{1} \approx - 0.18816, m_{2} \approx 0.18816

Show Solution