Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
3n−3
Evaluate
n+n−1+n−2
Write the repeated addition as multiplication
n×3−1−2
Use the commutative property to reorder the terms
3n−1−2
Solution
3n−3
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Factor the expression
3(n−1)
Evaluate
n+n−1+n−2
Add the terms
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Evaluate
n+n
Collect like terms by calculating the sum or difference of their coefficients
(1+1)n
Add the numbers
2n
2n−1+n−2
Add the terms
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Evaluate
2n−1+n
Add the terms
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Evaluate
2n+n
Collect like terms by calculating the sum or difference of their coefficients
(2+1)n
Add the numbers
3n
3n−1
3n−1−2
Subtract the numbers
3n−3
Solution
3(n−1)
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Find the roots
n=1
Evaluate
n+n−1+n−2
To find the roots of the expression,set the expression equal to 0
n+n−1+n−2=0
Add the terms
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Evaluate
n+n
Collect like terms by calculating the sum or difference of their coefficients
(1+1)n
Add the numbers
2n
2n−1+n−2=0
Add the terms
More Steps
Evaluate
2n−1+n
Add the terms
More Steps
Evaluate
2n+n
Collect like terms by calculating the sum or difference of their coefficients
(2+1)n
Add the numbers
3n
3n−1
3n−1−2=0
Subtract the numbers
3n−3=0
Move the constant to the right-hand side and change its sign
3n=0+3
Removing 0 doesn't change the value,so remove it from the expression
3n=3
Divide both sides
33n=33
Divide the numbers
n=33
Solution
More Steps
Evaluate
33
Reduce the numbers
11
Calculate
1
n=1
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