Question
Function
Find the first partial derivative with respect to u
Find the first partial derivative with respect to c
∂u∂p=c2
Evaluate
p=2×cu
Multiply the terms
p=c2u
Find the first partial derivative by treating the variable c as a constant and differentiating with respect to u
∂u∂p=∂u∂(c2u)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂u∂p=c2∂u∂(2u)c−2u×∂u∂(c)
Evaluate
More Steps

Evaluate
∂u∂(2u)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
2×∂u∂(u)
Use ∂x∂xn=nxn−1 to find derivative
2×1
Multiply the terms
2
∂u∂p=c22c−2u×∂u∂(c)
Use ∂x∂(c)=0 to find derivative
∂u∂p=c22c−2u×0
Any expression multiplied by 0 equals 0
∂u∂p=c22c−0
Removing 0 doesn't change the value,so remove it from the expression
∂u∂p=c22c
Solution
More Steps

Evaluate
c22c
Use the product rule aman=an−m to simplify the expression
c2−12
Reduce the fraction
c2
∂u∂p=c2
Show Solution

Solve the equation
Solve for c
Solve for p
Solve for u
c=p2u
Evaluate
p=2×cu
Multiply the terms
p=c2u
Swap the sides of the equation
c2u=p
Cross multiply
2u=cp
Simplify the equation
2u=pc
Swap the sides of the equation
pc=2u
Divide both sides
ppc=p2u
Solution
c=p2u
Show Solution
