Solve p^26-10-5 - ScanMath

Question

Simplify the expression

6 p^{2} - 15

Evaluate

p^{2} \times 6 - 10 - 5

Use the commutative property to reorder the terms

6 p^{2} - 10 - 5

Solution

6 p^{2} - 15

Show Solution

3 (2 p^{2} - 5)

Evaluate

p^{2} \times 6 - 10 - 5

Use the commutative property to reorder the terms

6 p^{2} - 10 - 5

Subtract the numbers

6 p^{2} - 15

Solution

3 (2 p^{2} - 5)

Show Solution

p_{1} = - \frac{10}{2}, p_{2} = \frac{10}{2}

Alternative Form

p_{1} \approx - 1.581139, p_{2} \approx 1.581139

Evaluate

p^{2} \times 6 - 10 - 5

To find the roots of the expression,set the expression equal to 0

p^{2} \times 6 - 10 - 5 = 0

Use the commutative property to reorder the terms

6 p^{2} - 10 - 5 = 0

Subtract the numbers

6 p^{2} - 15 = 0

Move the constant to the right-hand side and change its sign

6 p^{2} = 0 + 15

Removing 0 doesn't change the value,so remove it from the expression

6 p^{2} = 15

Divide both sides

\frac{6 p ^{2}}{6} = \frac{15}{6}

Divide the numbers

p^{2} = \frac{15}{6}

Cancel out the common factor 3

p^{2} = \frac{5}{2}

Take the root of both sides of the equation and remember to use both positive and negative roots

p = \pm \frac{5}{2}

Simplify the expression

More Steps

Evaluate

\frac{5}{2}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{5}{2}

Multiply by the Conjugate

\frac{5 \times 2}{2 \times 2}

Multiply the numbers

More Steps

Evaluate

5 \times 2

The product of roots with the same index is equal to the root of the product

5 \times 2

Calculate the product

10

\frac{10}{2 \times 2}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{10}{2}

p = \pm \frac{10}{2}

Separate the equation into 2 possible cases

p = \frac{10}{2} p = - \frac{10}{2}

Solution

p_{1} = - \frac{10}{2}, p_{2} = \frac{10}{2}

Alternative Form

p_{1} \approx - 1.581139, p_{2} \approx 1.581139

Show Solution