Solve p^28335-1 - ScanMath

Question

Simplify the expression

8335 p^{2} - 1

Evaluate

p^{2} \times 8335 - 1

Solution

8335 p^{2} - 1

Show Solution

p_{1} = - \frac{8335}{8335}, p_{2} = \frac{8335}{8335}

Alternative Form

p_{1} \approx - 0.010953, p_{2} \approx 0.010953

Evaluate

p^{2} \times 8335 - 1

To find the roots of the expression,set the expression equal to 0

p^{2} \times 8335 - 1 = 0

Use the commutative property to reorder the terms

8335 p^{2} - 1 = 0

Move the constant to the right-hand side and change its sign

8335 p^{2} = 0 + 1

Removing 0 doesn't change the value,so remove it from the expression

8335 p^{2} = 1

Divide both sides

\frac{8335 p ^{2}}{8335} = \frac{1}{8335}

Divide the numbers

p^{2} = \frac{1}{8335}

Take the root of both sides of the equation and remember to use both positive and negative roots

p = \pm \frac{1}{8335}

Simplify the expression

More Steps

Evaluate

\frac{1}{8335}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{1}{8335}

Simplify the radical expression

\frac{1}{8335}

Multiply by the Conjugate

\frac{8335}{8335 \times 8335}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{8335}{8335}

p = \pm \frac{8335}{8335}

Separate the equation into 2 possible cases

p = \frac{8335}{8335} p = - \frac{8335}{8335}

Solution

p_{1} = - \frac{8335}{8335}, p_{2} = \frac{8335}{8335}

Alternative Form

p_{1} \approx - 0.010953, p_{2} \approx 0.010953

Show Solution