Algebra
Calculus
Trigonometry
Matrix
Question
Factor the expression
p(p−1)(p2+p+1)
Evaluate
p4−p
Factor out p from the expression
p(p3−1)
Solution
More Steps
Evaluate
p3−1
Rewrite the expression in exponential form
p3−13
Use a3−b3=(a−b)(a2+ab+b2) to factor the expression
(p−1)(p2+p×1+12)
Any expression multiplied by 1 remains the same
(p−1)(p2+p+12)
1 raised to any power equals to 1
(p−1)(p2+p+1)
p(p−1)(p2+p+1)
Show Solution
Find the roots
p1=0,p2=1
Evaluate
p4−p
To find the roots of the expression,set the expression equal to 0
p4−p=0
Factor the expression
p(p3−1)=0
Separate the equation into 2 possible cases
p=0p3−1=0
Solve the equation
More Steps
Evaluate
p3−1=0
Move the constant to the right-hand side and change its sign
p3=0+1
Removing 0 doesn't change the value,so remove it from the expression
p3=1
Take the 3-th root on both sides of the equation
3p3=31
Calculate
p=31
Simplify the root
p=1
p=0p=1
Solution
p1=0,p2=1
Show Solution