Solve p7p-1 - ScanMath

Question

Simplify the expression

7 p^{2} - 1

Evaluate

p \times 7 p - 1

Solution

More Steps

Evaluate

p \times 7 p

Multiply the terms

p^{2} \times 7

Use the commutative property to reorder the terms

7 p^{2}

7 p^{2} - 1

Show Solution

p_{1} = - \frac{7}{7}, p_{2} = \frac{7}{7}

Alternative Form

p_{1} \approx - 0.377964, p_{2} \approx 0.377964

Evaluate

p \times 7 p - 1

To find the roots of the expression,set the expression equal to 0

p \times 7 p - 1 = 0

Multiply

More Steps

Multiply the terms

p \times 7 p

Multiply the terms

p^{2} \times 7

Use the commutative property to reorder the terms

7 p^{2}

7 p^{2} - 1 = 0

Move the constant to the right-hand side and change its sign

7 p^{2} = 0 + 1

Removing 0 doesn't change the value,so remove it from the expression

7 p^{2} = 1

Divide both sides

\frac{7 p ^{2}}{7} = \frac{1}{7}

Divide the numbers

p^{2} = \frac{1}{7}

Take the root of both sides of the equation and remember to use both positive and negative roots

p = \pm \frac{1}{7}

Simplify the expression

More Steps

Evaluate

\frac{1}{7}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{1}{7}

Simplify the radical expression

\frac{1}{7}

Multiply by the Conjugate

\frac{7}{7 \times 7}

When a square root of an expression is multiplied by itself,the result is that expression

\frac{7}{7}

p = \pm \frac{7}{7}

Separate the equation into 2 possible cases

p = \frac{7}{7} p = - \frac{7}{7}

Solution

p_{1} = - \frac{7}{7}, p_{2} = \frac{7}{7}

Alternative Form

p_{1} \approx - 0.377964, p_{2} \approx 0.377964

Show Solution