Question
Function
Find the first partial derivative with respect to v
Find the first partial derivative with respect to c
∂v∂q=c1
Simplify
q=cv
Find the first partial derivative by treating the variable c as a constant and differentiating with respect to v
∂v∂q=∂v∂(cv)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂v∂q=c2∂v∂(v)c−v×∂v∂(c)
Use ∂x∂xn=nxn−1 to find derivative
∂v∂q=c21×c−v×∂v∂(c)
Use ∂x∂(c)=0 to find derivative
∂v∂q=c21×c−v×0
Any expression multiplied by 1 remains the same
∂v∂q=c2c−v×0
Any expression multiplied by 0 equals 0
∂v∂q=c2c−0
Removing 0 doesn't change the value,so remove it from the expression
∂v∂q=c2c
Solution
More Steps

Evaluate
c2c
Use the product rule aman=an−m to simplify the expression
c2−11
Reduce the fraction
c1
∂v∂q=c1
Show Solution

Solve the equation
Solve for c
Solve for v
c=qv
Evaluate
q=cv
Swap the sides of the equation
cv=q
Cross multiply
v=cq
Simplify the equation
v=qc
Swap the sides of the equation
qc=v
Divide both sides
qqc=qv
Solution
c=qv
Show Solution
