Question
Function
Find the first partial derivative with respect to f
Find the first partial derivative with respect to p
∂f∂s=p1
Evaluate
s=f÷p
Rewrite the expression
s=pf
Find the first partial derivative by treating the variable p as a constant and differentiating with respect to f
∂f∂s=∂f∂(pf)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂f∂s=p2∂f∂(f)p−f×∂f∂(p)
Use ∂x∂xn=nxn−1 to find derivative
∂f∂s=p21×p−f×∂f∂(p)
Use ∂x∂(c)=0 to find derivative
∂f∂s=p21×p−f×0
Any expression multiplied by 1 remains the same
∂f∂s=p2p−f×0
Any expression multiplied by 0 equals 0
∂f∂s=p2p−0
Removing 0 doesn't change the value,so remove it from the expression
∂f∂s=p2p
Solution
More Steps

Evaluate
p2p
Use the product rule aman=an−m to simplify the expression
p2−11
Reduce the fraction
p1
∂f∂s=p1
Show Solution

Solve the equation
Solve for f
Solve for p
Solve for s
f=ps
Evaluate
s=f÷p
Rewrite the expression
s=pf
Swap the sides of the equation
pf=s
Solution
f=ps
Show Solution
