Solve s= t^3 - 6t^23t^4

Evaluate

s = t^{3} - 6 t^{2} \times 3 t^{4}

Simplify

More Steps

s = t^{3} - 18 t^{6}

Take the derivative of both sides

s^{'} = \frac{d}{d t} (t^{3} - 18 t^{6})

Use differentiation rule \frac{d}{d x} (f (x) \pm g (x)) = \frac{d}{d x} (f (x)) \pm \frac{d}{d x} (g (x))

s^{'} = \frac{d}{d t} (t^{3}) - \frac{d}{d t} (18 t^{6})

Use \frac{d}{d x} x^{n} = n x^{n - 1} to find derivative

s^{'} = 3 t^{2} - \frac{d}{d t} (18 t^{6})

Solution

More Steps

s^{'} = 3 t^{2} - 108 t^{5}

Function