Question
s=fp
Function
Find the first partial derivative with respect to p
Find the first partial derivative with respect to f
∂p∂s=f1
Simplify
s=fp
Find the first partial derivative by treating the variable f as a constant and differentiating with respect to p
∂p∂s=∂p∂(fp)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂p∂s=f2∂p∂(p)f−p×∂p∂(f)
Use ∂x∂xn=nxn−1 to find derivative
∂p∂s=f21×f−p×∂p∂(f)
Use ∂x∂(c)=0 to find derivative
∂p∂s=f21×f−p×0
Any expression multiplied by 1 remains the same
∂p∂s=f2f−p×0
Any expression multiplied by 0 equals 0
∂p∂s=f2f−0
Removing 0 doesn't change the value,so remove it from the expression
∂p∂s=f2f
Solution
More Steps

Evaluate
f2f
Use the product rule aman=an−m to simplify the expression
f2−11
Reduce the fraction
f1
∂p∂s=f1
Show Solution

Solve the equation
Solve for f
Solve for p
f=sp
Evaluate
s=fp
Swap the sides of the equation
fp=s
Cross multiply
p=fs
Simplify the equation
p=sf
Swap the sides of the equation
sf=p
Divide both sides
ssf=sp
Solution
f=sp
Show Solution
