Question
Function
Find the first partial derivative with respect to v
Find the first partial derivative with respect to t
∂v∂s=t1
Evaluate
s=v÷t
Rewrite the expression
s=tv
Find the first partial derivative by treating the variable t as a constant and differentiating with respect to v
∂v∂s=∂v∂(tv)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂v∂s=t2∂v∂(v)t−v×∂v∂(t)
Use ∂x∂xn=nxn−1 to find derivative
∂v∂s=t21×t−v×∂v∂(t)
Use ∂x∂(c)=0 to find derivative
∂v∂s=t21×t−v×0
Any expression multiplied by 1 remains the same
∂v∂s=t2t−v×0
Any expression multiplied by 0 equals 0
∂v∂s=t2t−0
Removing 0 doesn't change the value,so remove it from the expression
∂v∂s=t2t
Solution
More Steps

Evaluate
t2t
Use the product rule aman=an−m to simplify the expression
t2−11
Reduce the fraction
t1
∂v∂s=t1
Show Solution

Solve the equation
Solve for s
Solve for t
Solve for v
s=tv
Evaluate
s=v÷t
Solution
s=tv
Show Solution
