Question
Solve the quadratic equation
Solve using the quadratic formula
Solve by completing the square
Solve using the PQ formula
s1=15−258,s2=15+258
Alternative Form
s1≈−0.231546,s2≈30.231546
Evaluate
s2−30s−7=0
Substitute a=1,b=−30 and c=−7 into the quadratic formula s=2a−b±b2−4ac
s=230±(−30)2−4(−7)
Simplify the expression
More Steps

Evaluate
(−30)2−4(−7)
Multiply the numbers
More Steps

Evaluate
4(−7)
Multiplying or dividing an odd number of negative terms equals a negative
−4×7
Multiply the numbers
−28
(−30)2−(−28)
Rewrite the expression
302−(−28)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
302+28
Evaluate the power
900+28
Add the numbers
928
s=230±928
Simplify the radical expression
More Steps

Evaluate
928
Write the expression as a product where the root of one of the factors can be evaluated
16×58
Write the number in exponential form with the base of 4
42×58
The root of a product is equal to the product of the roots of each factor
42×58
Reduce the index of the radical and exponent with 2
458
s=230±458
Separate the equation into 2 possible cases
s=230+458s=230−458
Simplify the expression
More Steps

Evaluate
s=230+458
Divide the terms
More Steps

Evaluate
230+458
Rewrite the expression
22(15+258)
Reduce the fraction
15+258
s=15+258
s=15+258s=230−458
Simplify the expression
More Steps

Evaluate
s=230−458
Divide the terms
More Steps

Evaluate
230−458
Rewrite the expression
22(15−258)
Reduce the fraction
15−258
s=15−258
s=15+258s=15−258
Solution
s1=15−258,s2=15+258
Alternative Form
s1≈−0.231546,s2≈30.231546
Show Solution
