Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
135s2−801
Evaluate
s2×135−801−0
Use the commutative property to reorder the terms
135s2−801−0
Solution
135s2−801
Show Solution
Factor the expression
9(15s2−89)
Evaluate
s2×135−801−0
Use the commutative property to reorder the terms
135s2−801−0
Removing 0 doesn't change the value,so remove it from the expression
135s2−801
Solution
9(15s2−89)
Show Solution
Find the roots
s1=−151335,s2=151335
Alternative Form
s1≈−2.435843,s2≈2.435843
Evaluate
s2×135−801−0
To find the roots of the expression,set the expression equal to 0
s2×135−801−0=0
Use the commutative property to reorder the terms
135s2−801−0=0
Removing 0 doesn't change the value,so remove it from the expression
135s2−801=0
Move the constant to the right-hand side and change its sign
135s2=0+801
Removing 0 doesn't change the value,so remove it from the expression
135s2=801
Divide both sides
135135s2=135801
Divide the numbers
s2=135801
Cancel out the common factor 9
s2=1589
Take the root of both sides of the equation and remember to use both positive and negative roots
s=±1589
Simplify the expression
More Steps
Evaluate
1589
To take a root of a fraction,take the root of the numerator and denominator separately
1589
Multiply by the Conjugate
15×1589×15
Multiply the numbers
More Steps
Evaluate
89×15
The product of roots with the same index is equal to the root of the product
89×15
Calculate the product
1335
15×151335
When a square root of an expression is multiplied by itself,the result is that expression
151335
s=±151335
Separate the equation into 2 possible cases
s=151335s=−151335
Solution
s1=−151335,s2=151335
Alternative Form
s1≈−2.435843,s2≈2.435843
Show Solution