Algebra
Calculus
Trigonometry
Matrix
Question
Simplify the expression
5s2−7
Evaluate
s2×5−4−3
Use the commutative property to reorder the terms
5s2−4−3
Solution
5s2−7
Show Solution
Find the roots
s1=−535,s2=535
Alternative Form
s1≈−1.183216,s2≈1.183216
Evaluate
s2×5−4−3
To find the roots of the expression,set the expression equal to 0
s2×5−4−3=0
Use the commutative property to reorder the terms
5s2−4−3=0
Subtract the numbers
5s2−7=0
Move the constant to the right-hand side and change its sign
5s2=0+7
Removing 0 doesn't change the value,so remove it from the expression
5s2=7
Divide both sides
55s2=57
Divide the numbers
s2=57
Take the root of both sides of the equation and remember to use both positive and negative roots
s=±57
Simplify the expression
More Steps
Evaluate
57
To take a root of a fraction,take the root of the numerator and denominator separately
57
Multiply by the Conjugate
5×57×5
Multiply the numbers
More Steps
Evaluate
7×5
The product of roots with the same index is equal to the root of the product
7×5
Calculate the product
35
5×535
When a square root of an expression is multiplied by itself,the result is that expression
535
s=±535
Separate the equation into 2 possible cases
s=535s=−535
Solution
s1=−535,s2=535
Alternative Form
s1≈−1.183216,s2≈1.183216
Show Solution