Solve sin(\theta )(2 sin(\theta ) 1) = 0

Evaluate

sin (θ) (2 sin (θ) \times 1) = 0

Remove the parentheses

sin (θ) \times 2 sin (θ) \times 1 = 0

Multiply the terms

More Steps

2 sin^{2} (θ) = 0

Simplify the expression

sin (θ) = 0

Use the inverse trigonometric function

θ = arcsin (0)

Calculate

θ = 0

Solution

θ = kπ, k \in Z

Alternative Form

θ = 18 0^{\circ} k, k \in Z

Solve the equation