Question
Function
Find the first partial derivative with respect to v
Find the first partial derivative with respect to g
∂v∂t=g2
Evaluate
t=2×gv
Multiply the terms
t=g2v
Find the first partial derivative by treating the variable g as a constant and differentiating with respect to v
∂v∂t=∂v∂(g2v)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂v∂t=g2∂v∂(2v)g−2v×∂v∂(g)
Evaluate
More Steps

Evaluate
∂v∂(2v)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
2×∂v∂(v)
Use ∂x∂xn=nxn−1 to find derivative
2×1
Multiply the terms
2
∂v∂t=g22g−2v×∂v∂(g)
Use ∂x∂(c)=0 to find derivative
∂v∂t=g22g−2v×0
Any expression multiplied by 0 equals 0
∂v∂t=g22g−0
Removing 0 doesn't change the value,so remove it from the expression
∂v∂t=g22g
Solution
More Steps

Evaluate
g22g
Use the product rule aman=an−m to simplify the expression
g2−12
Reduce the fraction
g2
∂v∂t=g2
Show Solution

Solve the equation
Solve for g
Solve for t
Solve for v
g=t2v
Evaluate
t=2×gv
Multiply the terms
t=g2v
Swap the sides of the equation
g2v=t
Cross multiply
2v=gt
Simplify the equation
2v=tg
Swap the sides of the equation
tg=2v
Divide both sides
ttg=t2v
Solution
g=t2v
Show Solution
