Solve t=2*pi*m/k - ScanMath

Evaluate

t = 2 π \times \frac{m}{k}

Multiply the terms

t = \frac{2 πm}{k}

Find the first partial derivative by treating the variable k as a constant and differentiating with respect to m

\frac{\partial t}{\partial m} = \frac{\partial}{\partial m} (\frac{2 πm}{k})

Use differentiation rule \frac{\partial}{\partial x} (\frac{f ( x )}{g ( x )}) = \frac{\frac{\partial}{\partial x} ( f ( x )) \times g ( x ) - f ( x ) \times \frac{\partial}{\partial x} ( g ( x ) )}{( g ( x ) ) ^{2}}

\frac{\partial t}{\partial m} = \frac{\frac{\partial}{\partial m} ( 2 πm ) k - 2 πm \times \frac{\partial}{\partial m} ( k )}{k ^{2}}

Evaluate

More Steps

\frac{\partial t}{\partial m} = \frac{2 πk - 2 πm \times \frac{\partial}{\partial m} ( k )}{k ^{2}}

Use \frac{\partial}{\partial x} (c) = 0 to find derivative

\frac{\partial t}{\partial m} = \frac{2 πk - 2 πm \times 0}{k ^{2}}

Any expression multiplied by 0 equals 0

\frac{\partial t}{\partial m} = \frac{2 πk - 0}{k ^{2}}

Removing 0 doesn't change the value,so remove it from the expression

\frac{\partial t}{\partial m} = \frac{2 πk}{k ^{2}}

Solution

More Steps

\frac{\partial t}{\partial m} = \frac{2 π}{k}

Function