Question
Function
Find the first partial derivative with respect to u
Find the first partial derivative with respect to g
∂u∂t=g2
Evaluate
t=2×gu
Multiply the terms
t=g2u
Find the first partial derivative by treating the variable g as a constant and differentiating with respect to u
∂u∂t=∂u∂(g2u)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂u∂t=g2∂u∂(2u)g−2u×∂u∂(g)
Evaluate
More Steps

Evaluate
∂u∂(2u)
Use differentiation rule ∂x∂(cf(x))=c×∂x∂(f(x))
2×∂u∂(u)
Use ∂x∂xn=nxn−1 to find derivative
2×1
Multiply the terms
2
∂u∂t=g22g−2u×∂u∂(g)
Use ∂x∂(c)=0 to find derivative
∂u∂t=g22g−2u×0
Any expression multiplied by 0 equals 0
∂u∂t=g22g−0
Removing 0 doesn't change the value,so remove it from the expression
∂u∂t=g22g
Solution
More Steps

Evaluate
g22g
Use the product rule aman=an−m to simplify the expression
g2−12
Reduce the fraction
g2
∂u∂t=g2
Show Solution

Solve the equation
Solve for g
Solve for t
Solve for u
g=t2u
Evaluate
t=2×gu
Multiply the terms
t=g2u
Swap the sides of the equation
g2u=t
Cross multiply
2u=gt
Simplify the equation
2u=tg
Swap the sides of the equation
tg=2u
Divide both sides
ttg=t2u
Solution
g=t2u
Show Solution
