Solve t^2-2t-20=0

Evaluate

t^{2} - 2 t - 20 = 0

Substitute a= 1,b= - 2 and c= - 20 into the quadratic formula t = \frac{- b \pm b ^{2} - 4 a c}{2 a}

t = \frac{2 \pm ( - 2 ) ^{2} - 4 ( - 20 )}{2}

Simplify the expression

More Steps

t = \frac{2 \pm 84}{2}

Simplify the radical expression

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t = \frac{2 \pm 2 21}{2}

Separate the equation into 2 possible cases

t = \frac{2 + 2 21}{2} t = \frac{2 - 2 21}{2}

Simplify the expression

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t = 1 + 21 t = \frac{2 - 2 21}{2}

Simplify the expression

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t = 1 + 21 t = 1 - 21

Solution

t_{1} = 1 - 21, t_{2} = 1 + 21

Alternative Form

t_{1} \approx - 3.582576, t_{2} \approx 5.582576

Solve the quadratic equation