Question
Find the roots
t1=23−33,t2=23+33
Alternative Form
t1≈−1.372281,t2≈4.372281
Evaluate
t2−3t−6
To find the roots of the expression,set the expression equal to 0
t2−3t−6=0
Substitute a=1,b=−3 and c=−6 into the quadratic formula t=2a−b±b2−4ac
t=23±(−3)2−4(−6)
Simplify the expression
More Steps

Evaluate
(−3)2−4(−6)
Multiply the numbers
More Steps

Evaluate
4(−6)
Multiplying or dividing an odd number of negative terms equals a negative
−4×6
Multiply the numbers
−24
(−3)2−(−24)
Rewrite the expression
32−(−24)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
32+24
Evaluate the power
9+24
Add the numbers
33
t=23±33
Separate the equation into 2 possible cases
t=23+33t=23−33
Solution
t1=23−33,t2=23+33
Alternative Form
t1≈−1.372281,t2≈4.372281
Show Solution
