Question
Simplify the expression
840t2−78
Evaluate
t2×840−15−63
Use the commutative property to reorder the terms
840t2−15−63
Solution
840t2−78
Show Solution

Factor the expression
6(140t2−13)
Evaluate
t2×840−15−63
Use the commutative property to reorder the terms
840t2−15−63
Subtract the numbers
840t2−78
Solution
6(140t2−13)
Show Solution

Find the roots
t1=−70455,t2=70455
Alternative Form
t1≈−0.304725,t2≈0.304725
Evaluate
t2×840−15−63
To find the roots of the expression,set the expression equal to 0
t2×840−15−63=0
Use the commutative property to reorder the terms
840t2−15−63=0
Subtract the numbers
840t2−78=0
Move the constant to the right-hand side and change its sign
840t2=0+78
Removing 0 doesn't change the value,so remove it from the expression
840t2=78
Divide both sides
840840t2=84078
Divide the numbers
t2=84078
Cancel out the common factor 6
t2=14013
Take the root of both sides of the equation and remember to use both positive and negative roots
t=±14013
Simplify the expression
More Steps

Evaluate
14013
To take a root of a fraction,take the root of the numerator and denominator separately
14013
Simplify the radical expression
More Steps

Evaluate
140
Write the expression as a product where the root of one of the factors can be evaluated
4×35
Write the number in exponential form with the base of 2
22×35
The root of a product is equal to the product of the roots of each factor
22×35
Reduce the index of the radical and exponent with 2
235
23513
Multiply by the Conjugate
235×3513×35
Multiply the numbers
More Steps

Evaluate
13×35
The product of roots with the same index is equal to the root of the product
13×35
Calculate the product
455
235×35455
Multiply the numbers
More Steps

Evaluate
235×35
When a square root of an expression is multiplied by itself,the result is that expression
2×35
Multiply the terms
70
70455
t=±70455
Separate the equation into 2 possible cases
t=70455t=−70455
Solution
t1=−70455,t2=70455
Alternative Form
t1≈−0.304725,t2≈0.304725
Show Solution
