Question Factor the expression (t−1)(t2+t+1) Evaluate t3−1Rewrite the expression in exponential form t3−13Use a3−b3=(a−b)(a2+ab+b2) to factor the expression (t−1)(t2+t×1+12)Any expression multiplied by 1 remains the same (t−1)(t2+t+12)Solution (t−1)(t2+t+1) Show Solution Find the roots t=1 Evaluate t3−1To find the roots of the expression,set the expression equal to 0 t3−1=0Move the constant to the right-hand side and change its sign t3=0+1Removing 0 doesn't change the value,so remove it from the expression t3=1Take the 3-th root on both sides of the equation 3t3=31Calculate t=31Solution t=1 Show Solution
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