Solve t^4520-43324

Question

Simplify the expression

520 t^{4} - 43324

Evaluate

t^{4} \times 520 - 43324

Solution

520 t^{4} - 43324

Show Solution

4 (130 t^{4} - 10831)

Evaluate

t^{4} \times 520 - 43324

Use the commutative property to reorder the terms

520 t^{4} - 43324

Solution

4 (130 t^{4} - 10831)

Show Solution

t_{1} = - \frac{4 10831 \times 13 0 ^{3}}{130}, t_{2} = \frac{4 10831 \times 13 0 ^{3}}{130}

Alternative Form

t_{1} \approx - 3.021213, t_{2} \approx 3.021213

Evaluate

t^{4} \times 520 - 43324

To find the roots of the expression,set the expression equal to 0

t^{4} \times 520 - 43324 = 0

Use the commutative property to reorder the terms

520 t^{4} - 43324 = 0

Move the constant to the right-hand side and change its sign

520 t^{4} = 0 + 43324

Removing 0 doesn't change the value,so remove it from the expression

520 t^{4} = 43324

Divide both sides

\frac{520 t ^{4}}{520} = \frac{43324}{520}

Divide the numbers

t^{4} = \frac{43324}{520}

Cancel out the common factor 4

t^{4} = \frac{10831}{130}

Take the root of both sides of the equation and remember to use both positive and negative roots

t = \pm 4 \frac{10831}{130}

Simplify the expression

More Steps

Evaluate

4 \frac{10831}{130}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{4 10831}{4 130}

Multiply by the Conjugate

\frac{4 10831 \times 4 13 0 ^{3}}{4 130 \times 4 13 0 ^{3}}

The product of roots with the same index is equal to the root of the product

\frac{4 10831 \times 13 0 ^{3}}{4 130 \times 4 13 0 ^{3}}

Multiply the numbers

More Steps

Evaluate

4130 \times 4 13 0^{3}

The product of roots with the same index is equal to the root of the product

4 130 \times 13 0^{3}

Calculate the product

4 13 0^{4}

Reduce the index of the radical and exponent with 4

130

\frac{4 10831 \times 13 0 ^{3}}{130}

t = \pm \frac{4 10831 \times 13 0 ^{3}}{130}

Separate the equation into 2 possible cases

t = \frac{4 10831 \times 13 0 ^{3}}{130} t = - \frac{4 10831 \times 13 0 ^{3}}{130}

Solution

t_{1} = - \frac{4 10831 \times 13 0 ^{3}}{130}, t_{2} = \frac{4 10831 \times 13 0 ^{3}}{130}

Alternative Form

t_{1} \approx - 3.021213, t_{2} \approx 3.021213

Show Solution