Solve t^570-1-23 - ScanMath

Question

Simplify the expression

70 t^{5} - 24

Evaluate

t^{5} \times 70 - 1 - 23

Use the commutative property to reorder the terms

70 t^{5} - 1 - 23

Solution

70 t^{5} - 24

Show Solution

2 (35 t^{5} - 12)

Evaluate

t^{5} \times 70 - 1 - 23

Use the commutative property to reorder the terms

70 t^{5} - 1 - 23

Subtract the numbers

70 t^{5} - 24

Solution

2 (35 t^{5} - 12)

Show Solution

t = \frac{5 12 \times 3 5 ^{4}}{35}

Alternative Form

t \approx 0.807277

Evaluate

t^{5} \times 70 - 1 - 23

To find the roots of the expression,set the expression equal to 0

t^{5} \times 70 - 1 - 23 = 0

Use the commutative property to reorder the terms

70 t^{5} - 1 - 23 = 0

Subtract the numbers

70 t^{5} - 24 = 0

Move the constant to the right-hand side and change its sign

70 t^{5} = 0 + 24

Removing 0 doesn't change the value,so remove it from the expression

70 t^{5} = 24

Divide both sides

\frac{70 t ^{5}}{70} = \frac{24}{70}

Divide the numbers

t^{5} = \frac{24}{70}

Cancel out the common factor 2

t^{5} = \frac{12}{35}

Take the 5 -th root on both sides of the equation

5 t^{5} = 5 \frac{12}{35}

Calculate

t = 5 \frac{12}{35}

Solution

More Steps

Evaluate

5 \frac{12}{35}

To take a root of a fraction,take the root of the numerator and denominator separately

\frac{5 12}{5 35}

Multiply by the Conjugate

\frac{5 12 \times 5 3 5 ^{4}}{5 35 \times 5 3 5 ^{4}}

The product of roots with the same index is equal to the root of the product

\frac{5 12 \times 3 5 ^{4}}{5 35 \times 5 3 5 ^{4}}

Multiply the numbers

More Steps

Evaluate

535 \times 5 3 5^{4}

The product of roots with the same index is equal to the root of the product

5 35 \times 3 5^{4}

Calculate the product

5 3 5^{5}

Reduce the index of the radical and exponent with 5

35

\frac{5 12 \times 3 5 ^{4}}{35}

t = \frac{5 12 \times 3 5 ^{4}}{35}

Alternative Form

t \approx 0.807277

Show Solution