Solve t(n)=2*t(n-1) 1

Evaluate

t (n) = 2 t (n - 1) \times 1

Any expression multiplied by 1 remains the same

t (n) = 2 t (n - 1)

Take the derivative of both sides

t^{'} (n) = \frac{d}{d n} (2 t (n - 1))

Calculate

t^{'} (n) = \frac{d}{d n} (2 t n - 2 t)

Use differentiation rule \frac{d}{d x} (f (x) \pm g (x)) = \frac{d}{d x} (f (x)) \pm \frac{d}{d x} (g (x))

t^{'} (n) = \frac{d}{d n} (2 t n) + \frac{d}{d n} (- 2 t)

Calculate

More Steps

t^{'} (n) = 2 t + \frac{d}{d n} (- 2 t)

Use \frac{d}{d x} (c) = 0 to find derivative

t^{'} (n) = 2 t + 0

Solution

t^{'} (n) = 2 t

Function