Solve t(n)=4t(2n^2) n

Evaluate

t (n) = 4 t \times 2 n^{2} \times n

Simplify

More Steps

t (n) = 8 t n^{3}

Take the derivative of both sides

t^{'} (n) = \frac{d}{d n} (8 t n^{3})

Use differentiation rule \frac{d}{d x} (c f (x)) = c \times \frac{d}{d x} (f (x))

t^{'} (n) = 8 t \times \frac{d}{d n} (n^{3})

Use \frac{d}{d x} x^{n} = n x^{n - 1} to find derivative

t^{'} (n) = 8 t \times 3 n^{2}

Solution

t^{'} (n) = 24 t n^{2}

Function