Question
Function
Find the first partial derivative with respect to j
Find the first partial derivative with respect to c
∂j∂v=c1
Simplify
v=cj
Find the first partial derivative by treating the variable c as a constant and differentiating with respect to j
∂j∂v=∂j∂(cj)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂j∂v=c2∂j∂(j)c−j×∂j∂(c)
Use ∂x∂xn=nxn−1 to find derivative
∂j∂v=c21×c−j×∂j∂(c)
Use ∂x∂(c)=0 to find derivative
∂j∂v=c21×c−j×0
Any expression multiplied by 1 remains the same
∂j∂v=c2c−j×0
Any expression multiplied by 0 equals 0
∂j∂v=c2c−0
Removing 0 doesn't change the value,so remove it from the expression
∂j∂v=c2c
Solution
More Steps

Evaluate
c2c
Use the product rule aman=an−m to simplify the expression
c2−11
Reduce the fraction
c1
∂j∂v=c1
Show Solution

Solve the equation
Solve for c
Solve for j
c=vj
Evaluate
v=cj
Swap the sides of the equation
cj=v
Cross multiply
j=cv
Simplify the equation
j=vc
Swap the sides of the equation
vc=j
Divide both sides
vvc=vj
Solution
c=vj
Show Solution
