Solve v 8(v-4)-6v=-12

Question

Solve the quadratic equation

Solve using the quadratic formula

Solve by completing the square

Solve using the PQ formula

v_{1} = \frac{19 - 265}{8}, v_{2} = \frac{19 + 265}{8}

Alternative Form

v_{1} \approx 0.340147, v_{2} \approx 4.409853

Evaluate

v \times 8 (v - 4) - 6 v = - 12

Use the commutative property to reorder the terms

8 v (v - 4) - 6 v = - 12

Expand the expression

More Steps

8 v^{2} - 38 v = - 12

Move the expression to the left side

8 v^{2} - 38 v + 12 = 0

Substitute a= 8,b= - 38 and c= 12 into the quadratic formula v = \frac{- b \pm b ^{2} - 4 a c}{2 a}

v = \frac{38 \pm ( - 38 ) ^{2} - 4 \times 8 \times 12}{2 \times 8}

Simplify the expression

v = \frac{38 \pm ( - 38 ) ^{2} - 4 \times 8 \times 12}{16}

Simplify the expression

More Steps

v = \frac{38 \pm 1060}{16}

Simplify the radical expression

More Steps

v = \frac{38 \pm 2 265}{16}

Separate the equation into 2 possible cases

v = \frac{38 + 2 265}{16} v = \frac{38 - 2 265}{16}

Simplify the expression

More Steps

v = \frac{19 + 265}{8} v = \frac{38 - 2 265}{16}

Simplify the expression

More Steps

v = \frac{19 + 265}{8} v = \frac{19 - 265}{8}

Solution

v_{1} = \frac{19 - 265}{8}, v_{2} = \frac{19 + 265}{8}

Alternative Form

v_{1} \approx 0.340147, v_{2} \approx 4.409853

Show Solution