Question
Solve the quadratic equation
Solve using the quadratic formula
Solve by completing the square
Solve using the PQ formula
v1=6−85,v2=6+85
Alternative Form
v1≈−3.219544,v2≈15.219544
Evaluate
v2−12v−49=0
Substitute a=1,b=−12 and c=−49 into the quadratic formula v=2a−b±b2−4ac
v=212±(−12)2−4(−49)
Simplify the expression
More Steps

Evaluate
(−12)2−4(−49)
Multiply the numbers
More Steps

Evaluate
4(−49)
Multiplying or dividing an odd number of negative terms equals a negative
−4×49
Multiply the numbers
−196
(−12)2−(−196)
Rewrite the expression
122−(−196)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
122+196
Evaluate the power
144+196
Add the numbers
340
v=212±340
Simplify the radical expression
More Steps

Evaluate
340
Write the expression as a product where the root of one of the factors can be evaluated
4×85
Write the number in exponential form with the base of 2
22×85
The root of a product is equal to the product of the roots of each factor
22×85
Reduce the index of the radical and exponent with 2
285
v=212±285
Separate the equation into 2 possible cases
v=212+285v=212−285
Simplify the expression
More Steps

Evaluate
v=212+285
Divide the terms
More Steps

Evaluate
212+285
Rewrite the expression
22(6+85)
Reduce the fraction
6+85
v=6+85
v=6+85v=212−285
Simplify the expression
More Steps

Evaluate
v=212−285
Divide the terms
More Steps

Evaluate
212−285
Rewrite the expression
22(6−85)
Reduce the fraction
6−85
v=6−85
v=6+85v=6−85
Solution
v1=6−85,v2=6+85
Alternative Form
v1≈−3.219544,v2≈15.219544
Show Solution
