Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
Solve for v
v∈(−∞,−4)∪(4,+∞)
Evaluate
v×v−12>4
Multiply the terms
v2−12>4
Move the expression to the left side
v2−12−4>0
Subtract the numbers
v2−16>0
Rewrite the expression
v2−16=0
Move the constant to the right-hand side and change its sign
v2=0+16
Removing 0 doesn't change the value,so remove it from the expression
v2=16
Take the root of both sides of the equation and remember to use both positive and negative roots
v=±16
Simplify the expression
More Steps

Evaluate
16
Write the number in exponential form with the base of 4
42
Reduce the index of the radical and exponent with 2
4
v=±4
Separate the equation into 2 possible cases
v=4v=−4
Determine the test intervals using the critical values
v<−4−4<v<4v>4
Choose a value form each interval
v1=−5v2=0v3=5
To determine if v<−4 is the solution to the inequality,test if the chosen value v=−5 satisfies the initial inequality
More Steps

Evaluate
(−5)2−12>4
Subtract the numbers
More Steps

Evaluate
(−5)2−12
Simplify
52−12
Evaluate the power
25−12
Subtract the numbers
13
13>4
Check the inequality
true
v<−4 is the solutionv2=0v3=5
To determine if −4<v<4 is the solution to the inequality,test if the chosen value v=0 satisfies the initial inequality
More Steps

Evaluate
02−12>4
Simplify
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Evaluate
02−12
Calculate
0−12
Removing 0 doesn't change the value,so remove it from the expression
−12
−12>4
Check the inequality
false
v<−4 is the solution−4<v<4 is not a solutionv3=5
To determine if v>4 is the solution to the inequality,test if the chosen value v=5 satisfies the initial inequality
More Steps

Evaluate
52−12>4
Subtract the numbers
More Steps

Evaluate
52−12
Evaluate the power
25−12
Subtract the numbers
13
13>4
Check the inequality
true
v<−4 is the solution−4<v<4 is not a solutionv>4 is the solution
Solution
v∈(−∞,−4)∪(4,+∞)
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