Solve w^2-5w-5=0 - ScanMath

Evaluate

w^{2} - 5 w - 5 = 0

Substitute a= 1,b= - 5 and c= - 5 into the quadratic formula w = \frac{- b \pm b ^{2} - 4 a c}{2 a}

w = \frac{5 \pm ( - 5 ) ^{2} - 4 ( - 5 )}{2}

Simplify the expression

More Steps

w = \frac{5 \pm 45}{2}

Simplify the radical expression

More Steps

w = \frac{5 \pm 3 5}{2}

Separate the equation into 2 possible cases

w = \frac{5 + 3 5}{2} w = \frac{5 - 3 5}{2}

Solution

w_{1} = \frac{5 - 3 5}{2}, w_{2} = \frac{5 + 3 5}{2}

Alternative Form

w_{1} \approx - 0.854102, w_{2} \approx 5.854102

Solve the quadratic equation