Question
Function
Find the first partial derivative with respect to c
Find the first partial derivative with respect to b
∂c∂x=−b1
Simplify
x=−bc
Find the first partial derivative by treating the variable b as a constant and differentiating with respect to c
∂c∂x=∂c∂(−bc)
Use differentiation rule ∂x∂(g(x)f(x))=(g(x))2∂x∂(f(x))×g(x)−f(x)×∂x∂(g(x))
∂c∂x=−b2∂c∂(c)b−c×∂c∂(b)
Use ∂x∂xn=nxn−1 to find derivative
∂c∂x=−b21×b−c×∂c∂(b)
Use ∂x∂(c)=0 to find derivative
∂c∂x=−b21×b−c×0
Any expression multiplied by 1 remains the same
∂c∂x=−b2b−c×0
Any expression multiplied by 0 equals 0
∂c∂x=−b2b−0
Removing 0 doesn't change the value,so remove it from the expression
∂c∂x=−b2b
Solution
More Steps

Evaluate
b2b
Use the product rule aman=an−m to simplify the expression
b2−11
Reduce the fraction
b1
∂c∂x=−b1
Show Solution

Solve the equation
Solve for b
Solve for c
b=−xc
Evaluate
x=−bc
Swap the sides of the equation
−bc=x
Rewrite the expression
b−c=x
Cross multiply
−c=bx
Simplify the equation
−c=xb
Swap the sides of the equation
xb=−c
Divide both sides
xxb=x−c
Divide the numbers
b=x−c
Solution
b=−xc
Show Solution
