Solve x 15(x-1)=1

Evaluate

x \times 15 (x - 1) = 1

Use the commutative property to reorder the terms

15 x (x - 1) = 1

Expand the expression

More Steps

15 x^{2} - 15 x = 1

Move the expression to the left side

15 x^{2} - 15 x - 1 = 0

Substitute a= 15,b= - 15 and c= - 1 into the quadratic formula x = \frac{- b \pm b ^{2} - 4 a c}{2 a}

x = \frac{15 \pm ( - 15 ) ^{2} - 4 \times 15 ( - 1 )}{2 \times 15}

Simplify the expression

x = \frac{15 \pm ( - 15 ) ^{2} - 4 \times 15 ( - 1 )}{30}

Simplify the expression

More Steps

x = \frac{15 \pm 285}{30}

Separate the equation into 2 possible cases

x = \frac{15 + 285}{30} x = \frac{15 - 285}{30}

Solution

x_{1} = \frac{15 - 285}{30}, x_{2} = \frac{15 + 285}{30}

Alternative Form

x_{1} \approx - 0.062731, x_{2} \approx 1.062731

Solve the quadratic equation