Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
x∈(−∞,0)∪(2,+∞)
Evaluate
x−2x>0
Find the domain
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Evaluate
x−2=0
Move the constant to the right side
x=0+2
Removing 0 doesn't change the value,so remove it from the expression
x=2
x−2x>0,x=2
Set the numerator and denominator of x−2x equal to 0 to find the values of x where sign changes may occur
x=0x−2=0
Calculate
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Evaluate
x−2=0
Move the constant to the right-hand side and change its sign
x=0+2
Removing 0 doesn't change the value,so remove it from the expression
x=2
x=0x=2
Determine the test intervals using the critical values
x<00<x<2x>2
Choose a value form each interval
x1=−1x2=1x3=3
To determine if x<0 is the solution to the inequality,test if the chosen value x=−1 satisfies the initial inequality
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Evaluate
−1−2−1>0
Simplify
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Evaluate
−1−2−1
Subtract the numbers
−3−1
Cancel out the common factor −1
31
31>0
Calculate
0.3˙>0
Check the inequality
true
x<0 is the solutionx2=1x3=3
To determine if 0<x<2 is the solution to the inequality,test if the chosen value x=1 satisfies the initial inequality
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Evaluate
1−21>0
Simplify
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Evaluate
1−21
Subtract the numbers
−11
Divide the terms
−1
−1>0
Check the inequality
false
x<0 is the solution0<x<2 is not a solutionx3=3
To determine if x>2 is the solution to the inequality,test if the chosen value x=3 satisfies the initial inequality
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Evaluate
3−23>0
Simplify
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Evaluate
3−23
Subtract the numbers
13
Divide the terms
3
3>0
Check the inequality
true
x<0 is the solution0<x<2 is not a solutionx>2 is the solution
The original inequality is a strict inequality,so does not include the critical value ,the final solution is x∈(−∞,0)∪(2,+∞)
x∈(−∞,0)∪(2,+∞)
Check if the solution is in the defined range
x∈(−∞,0)∪(2,+∞),x=2
Solution
x∈(−∞,0)∪(2,+∞)
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