Question
Solve the inequality
Solve the inequality by testing the values in the interval
Solve the inequality by separating into cases
0<x<31
Alternative Form
x∈(0,31)
Evaluate
x÷(∣x×1∣∣x∣)>3
Find the domain
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Evaluate
∣x×1∣∣x∣=0
Simplify
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Evaluate
∣x×1∣∣x∣
Any expression multiplied by 1 remains the same
∣x∣∣x∣
Multiply the terms
x2
x2=0
The only way a power can not be 0 is when the base not equals 0
x=0
x÷(∣x×1∣∣x∣)>3,x=0
Simplify
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Evaluate
x÷(∣x×1∣∣x∣)
Any expression multiplied by 1 remains the same
x÷(∣x∣∣x∣)
Multiply the terms
x÷x2
Rewrite the expression
x2x
Use the product rule aman=an−m to simplify the expression
x2−11
Reduce the fraction
x1
x1>3
Move the expression to the left side
x1−3>0
Subtract the terms
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Evaluate
x1−3
Reduce fractions to a common denominator
x1−x3x
Write all numerators above the common denominator
x1−3x
x1−3x>0
Set the numerator and denominator of x1−3x equal to 0 to find the values of x where sign changes may occur
1−3x=0x=0
Calculate
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Evaluate
1−3x=0
Move the constant to the right-hand side and change its sign
−3x=0−1
Removing 0 doesn't change the value,so remove it from the expression
−3x=−1
Change the signs on both sides of the equation
3x=1
Divide both sides
33x=31
Divide the numbers
x=31
x=31x=0
Determine the test intervals using the critical values
x<00<x<31x>31
Choose a value form each interval
x1=−1x2=61x3=2
To determine if x<0 is the solution to the inequality,test if the chosen value x=−1 satisfies the initial inequality
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Evaluate
−11>3
Divide the terms
−1>3
Check the inequality
false
x<0 is not a solutionx2=61x3=2
To determine if 0<x<31 is the solution to the inequality,test if the chosen value x=61 satisfies the initial inequality
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Evaluate
611>3
Multiply by the reciprocal
6>3
Check the inequality
true
x<0 is not a solution0<x<31 is the solutionx3=2
To determine if x>31 is the solution to the inequality,test if the chosen value x=2 satisfies the initial inequality
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Evaluate
21>3
Calculate
0.5>3
Check the inequality
false
x<0 is not a solution0<x<31 is the solutionx>31 is not a solution
The original inequality is a strict inequality,so does not include the critical value ,the final solution is 0<x<31
0<x<31
Check if the solution is in the defined range
0<x<31,x=0
Solution
0<x<31
Alternative Form
x∈(0,31)
Show Solution
