Solve x^(2) x≥0

Evaluate

x^{2} \times x \geq 0

Multiply the terms

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x^{3} \geq 0

Rewrite the expression

x^{3} = 0

Rewrite the expression

x^{2} \times x = 0

Separate the equation into 2 possible cases

x^{2} = 0 x = 0

The only way a power can be 0 is when the base equals 0

x = 0 x = 0

Find the union

x = 0

Determine the test intervals using the critical values

x < 0 x > 0

Choose a value form each interval

x_{1} = - 1 x_{2} = 1

To determine if x < 0 is the solution to the inequality,test if the chosen value x = - 1 satisfies the initial inequality

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x < 0 is not a solution x_{2} = 1

To determine if x > 0 is the solution to the inequality,test if the chosen value x = 1 satisfies the initial inequality

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x < 0 is not a solution x > 0 is the solution

The original inequality is a nonstrict inequality,so include the critical value in the solution

x \geq 0 is the solution

Solution

x \geq 0

Alternative Form

x \in [0, + \infty)

Solve the inequality