Algebra
Calculus
Trigonometry
Matrix
Question
Find the roots
x1=5−29,x2=5+29
Alternative Form
x1≈−0.385165,x2≈10.385165
Evaluate
x2−10x−4
To find the roots of the expression,set the expression equal to 0
x2−10x−4=0
Substitute a=1,b=−10 and c=−4 into the quadratic formula x=2a−b±b2−4ac
x=210±(−10)2−4(−4)
Simplify the expression
More Steps
Evaluate
(−10)2−4(−4)
Multiply the numbers
More Steps
Evaluate
4(−4)
Multiplying or dividing an odd number of negative terms equals a negative
−4×4
Multiply the numbers
−16
(−10)2−(−16)
Rewrite the expression
102−(−16)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
102+16
Evaluate the power
100+16
Add the numbers
116
x=210±116
Simplify the radical expression
More Steps
Evaluate
116
Write the expression as a product where the root of one of the factors can be evaluated
4×29
Write the number in exponential form with the base of 2
22×29
The root of a product is equal to the product of the roots of each factor
22×29
Reduce the index of the radical and exponent with 2
229
x=210±229
Separate the equation into 2 possible cases
x=210+229x=210−229
Simplify the expression
More Steps
Evaluate
x=210+229
Divide the terms
More Steps
Evaluate
210+229
Rewrite the expression
22(5+29)
Reduce the fraction
5+29
x=5+29
x=5+29x=210−229
Simplify the expression
More Steps
Evaluate
x=210−229
Divide the terms
More Steps
Evaluate
210−229
Rewrite the expression
22(5−29)
Reduce the fraction
5−29
x=5−29
x=5+29x=5−29
Solution
x1=5−29,x2=5+29
Alternative Form
x1≈−0.385165,x2≈10.385165
Show Solution
