Question
Solve the quadratic equation
Solve using the quadratic formula
Solve by completing the square
Solve using the PQ formula
x1=235−597,x2=235+597
Alternative Form
x1≈−7.122145,x2≈42.122145
Evaluate
x2−35x−300=0
Substitute a=1,b=−35 and c=−300 into the quadratic formula x=2a−b±b2−4ac
x=235±(−35)2−4(−300)
Simplify the expression
More Steps

Evaluate
(−35)2−4(−300)
Multiply the numbers
More Steps

Evaluate
4(−300)
Multiplying or dividing an odd number of negative terms equals a negative
−4×300
Multiply the numbers
−1200
(−35)2−(−1200)
Rewrite the expression
352−(−1200)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
352+1200
Evaluate the power
1225+1200
Add the numbers
2425
x=235±2425
Simplify the radical expression
More Steps

Evaluate
2425
Write the expression as a product where the root of one of the factors can be evaluated
25×97
Write the number in exponential form with the base of 5
52×97
The root of a product is equal to the product of the roots of each factor
52×97
Reduce the index of the radical and exponent with 2
597
x=235±597
Separate the equation into 2 possible cases
x=235+597x=235−597
Solution
x1=235−597,x2=235+597
Alternative Form
x1≈−7.122145,x2≈42.122145
Show Solution
