Question
Solve the equation
Solve for x
Solve for λ
x=21+2λ+1+4λ2x=21+2λ−1+4λ2
Evaluate
x2−x=λ(2x−1)
Move the expression to the left side
x2−x−λ(2x−1)=0
Calculate
More Steps

Evaluate
−λ(2x−1)
Apply the distributive property
−λ×2x−(−λ×1)
Use the commutative property to reorder the terms
−2λx−(−λ×1)
Multiply the numbers
−2λx−(−λ)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
−2λx+λ
x2−x−2λx+λ=0
Collect like terms by calculating the sum or difference of their coefficients
x2+(−1−2λ)x+λ=0
Substitute a=1,b=−1−2λ and c=λ into the quadratic formula x=2a−b±b2−4ac
x=21+2λ±(−1−2λ)2−4λ
Simplify the expression
More Steps

Evaluate
(−1−2λ)2−4λ
Evaluate the power
More Steps

Evaluate
(−1−2λ)2
A negative base raised to an even power equals a positive
(1+2λ)2
Use (a+b)2=a2+2ab+b2 to expand the expression
12+2×1×2λ+(2λ)2
Calculate
1+4λ+4λ2
1+4λ+4λ2−4λ
Since two opposites add up to 0,remove them form the expression
1+4λ2
x=21+2λ±1+4λ2
Solution
x=21+2λ+1+4λ2x=21+2λ−1+4λ2
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