Question
Solve the equation
Solve for x
Solve for y
Solve for z
x=22−2y−z2x=−22−2y−z2
Evaluate
x2+(y−3)×2+z2=16
Multiply the terms
x2+2(y−3)+z2=16
Rewrite the expression
x2+2y−6+z2=16
Move the expression to the right-hand side and change its sign
x2=16−(2y−6+z2)
Subtract the terms
More Steps

Evaluate
16−(2y−6+z2)
If a negative sign or a subtraction symbol appears outside parentheses, remove the parentheses and change the sign of every term within the parentheses
16−2y+6−z2
Add the numbers
22−2y−z2
x2=22−2y−z2
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±22−2y−z2
Solution
x=22−2y−z2x=−22−2y−z2
Show Solution

Find the partial derivative
Find ∂x∂z by differentiating the equation directly
Find ∂y∂z by differentiating the equation directly
∂x∂z=−zx
Evaluate
x2+(y−3)×2+z2=16
Multiply the terms
x2+2(y−3)+z2=16
Find ∂x∂z by taking the derivative of both sides with respect to x
∂x∂(x2+2(y−3)+z2)=∂x∂(16)
Use differentiation rule ∂x∂(f(x)±g(x))=∂x∂(f(x))±∂x∂(g(x))
∂x∂(x2)+∂x∂(2(y−3))+∂x∂(z2)=∂x∂(16)
Use ∂x∂xn=nxn−1 to find derivative
2x+∂x∂(2(y−3))+∂x∂(z2)=∂x∂(16)
Use ∂x∂(c)=0 to find derivative
2x+0+∂x∂(z2)=∂x∂(16)
Evaluate
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Evaluate
∂x∂(z2)
Use the chain rule ∂x∂(f(g))=∂g∂(f(g))×∂x∂(g) where the g=z, to find the derivative
∂z∂(z2)∂x∂z
Find the derivative
2z∂x∂z
2x+0+2z∂x∂z=∂x∂(16)
Removing 0 doesn't change the value,so remove it from the expression
2x+2z∂x∂z=∂x∂(16)
Find the partial derivative
2x+2z∂x∂z=0
Move the expression to the right-hand side and change its sign
2z∂x∂z=0−2x
Removing 0 doesn't change the value,so remove it from the expression
2z∂x∂z=−2x
Divide both sides
2z2z∂x∂z=2z−2x
Divide the numbers
∂x∂z=2z−2x
Solution
More Steps

Evaluate
2z−2x
Cancel out the common factor 2
z−x
Use b−a=−ba=−ba to rewrite the fraction
−zx
∂x∂z=−zx
Show Solution
