Question
Function
Find the x-intercept/zero
Find the y-intercept
x1=−2,x2=2
Evaluate
x2+2y=4
To find the x-intercept,set y=0
x2+2×0=4
Any expression multiplied by 0 equals 0
x2+0=4
Removing 0 doesn't change the value,so remove it from the expression
x2=4
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±4
Simplify the expression
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Evaluate
4
Write the number in exponential form with the base of 2
22
Reduce the index of the radical and exponent with 2
2
x=±2
Separate the equation into 2 possible cases
x=2x=−2
Solution
x1=−2,x2=2
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Solve the equation
Solve for x
Solve for y
x=4−2yx=−4−2y
Evaluate
x2+2y=4
Move the expression to the right-hand side and change its sign
x2=4−2y
Take the root of both sides of the equation and remember to use both positive and negative roots
x=±4−2y
Solution
x=4−2yx=−4−2y
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Testing for symmetry
Testing for symmetry about the origin
Testing for symmetry about the x-axis
Testing for symmetry about the y-axis
Not symmetry with respect to the origin
Evaluate
x2+2y=4
To test if the graph of x2+2y=4 is symmetry with respect to the origin,substitute -x for x and -y for y
(−x)2+2(−y)=4
Evaluate
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Evaluate
(−x)2+2(−y)
Multiply the numbers
(−x)2−2y
Rewrite the expression
x2−2y
x2−2y=4
Solution
Not symmetry with respect to the origin
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Identify the conic
Find the standard equation of the parabola
Find the vertex of the parabola
Find the focus of the parabola
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x2=−2(y−2)
Evaluate
x2+2y=4
Move the expression to the right-hand side and change its sign
x2=4−2y
Use the commutative property to reorder the terms
x2=−2y+4
Solution
x2=−2(y−2)
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Rewrite the equation
r=cos2(θ)−sin(θ)+1+3cos2(θ)r=−cos2(θ)sin(θ)+1+3cos2(θ)
Evaluate
x2+2y=4
To convert the equation to polar coordinates,substitute x for rcos(θ) and y for rsin(θ)
(cos(θ)×r)2+2sin(θ)×r=4
Factor the expression
cos2(θ)×r2+2sin(θ)×r=4
Subtract the terms
cos2(θ)×r2+2sin(θ)×r−4=4−4
Evaluate
cos2(θ)×r2+2sin(θ)×r−4=0
Solve using the quadratic formula
r=2cos2(θ)−2sin(θ)±(2sin(θ))2−4cos2(θ)(−4)
Simplify
r=2cos2(θ)−2sin(θ)±4+12cos2(θ)
Separate the equation into 2 possible cases
r=2cos2(θ)−2sin(θ)+4+12cos2(θ)r=2cos2(θ)−2sin(θ)−4+12cos2(θ)
Evaluate
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Evaluate
2cos2(θ)−2sin(θ)+4+12cos2(θ)
Simplify the root
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Evaluate
4+12cos2(θ)
Factor the expression
4(1+3cos2(θ))
Write the number in exponential form with the base of 2
22(1+3cos2(θ))
Calculate
21+3cos2(θ)
2cos2(θ)−2sin(θ)+21+3cos2(θ)
Factor
2cos2(θ)2(−sin(θ)+1+3cos2(θ))
Reduce the fraction
cos2(θ)−sin(θ)+1+3cos2(θ)
r=cos2(θ)−sin(θ)+1+3cos2(θ)r=2cos2(θ)−2sin(θ)−4+12cos2(θ)
Solution
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Evaluate
2cos2(θ)−2sin(θ)−4+12cos2(θ)
Simplify the root
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Evaluate
4+12cos2(θ)
Factor the expression
4(1+3cos2(θ))
Write the number in exponential form with the base of 2
22(1+3cos2(θ))
Calculate
21+3cos2(θ)
2cos2(θ)−2sin(θ)−21+3cos2(θ)
Use b−a=−ba=−ba to rewrite the fraction
−2cos2(θ)2sin(θ)+21+3cos2(θ)
Factor
−2cos2(θ)2(sin(θ)+1+3cos2(θ))
Reduce the fraction
−cos2(θ)sin(θ)+1+3cos2(θ)
r=cos2(θ)−sin(θ)+1+3cos2(θ)r=−cos2(θ)sin(θ)+1+3cos2(θ)
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Find the first derivative
Find the derivative with respect to x
Find the derivative with respect to y
dxdy=−x
Calculate
x2+2y=4
Take the derivative of both sides
dxd(x2+2y)=dxd(4)
Calculate the derivative
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Evaluate
dxd(x2+2y)
Use differentiation rules
dxd(x2)+dxd(2y)
Use dxdxn=nxn−1 to find derivative
2x+dxd(2y)
Evaluate the derivative
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Evaluate
dxd(2y)
Use differentiation rules
dyd(2y)×dxdy
Evaluate the derivative
2dxdy
2x+2dxdy
2x+2dxdy=dxd(4)
Calculate the derivative
2x+2dxdy=0
Move the expression to the right-hand side and change its sign
2dxdy=0−2x
Removing 0 doesn't change the value,so remove it from the expression
2dxdy=−2x
Divide both sides
22dxdy=2−2x
Divide the numbers
dxdy=2−2x
Solution
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Evaluate
2−2x
Reduce the numbers
1−x
Calculate
−x
dxdy=−x
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Find the second derivative
Find the second derivative with respect to x
Find the second derivative with respect to y
dx2d2y=−1
Calculate
x2+2y=4
Take the derivative of both sides
dxd(x2+2y)=dxd(4)
Calculate the derivative
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Evaluate
dxd(x2+2y)
Use differentiation rules
dxd(x2)+dxd(2y)
Use dxdxn=nxn−1 to find derivative
2x+dxd(2y)
Evaluate the derivative
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Evaluate
dxd(2y)
Use differentiation rules
dyd(2y)×dxdy
Evaluate the derivative
2dxdy
2x+2dxdy
2x+2dxdy=dxd(4)
Calculate the derivative
2x+2dxdy=0
Move the expression to the right-hand side and change its sign
2dxdy=0−2x
Removing 0 doesn't change the value,so remove it from the expression
2dxdy=−2x
Divide both sides
22dxdy=2−2x
Divide the numbers
dxdy=2−2x
Divide the numbers
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Evaluate
2−2x
Reduce the numbers
1−x
Calculate
−x
dxdy=−x
Take the derivative of both sides
dxd(dxdy)=dxd(−x)
Calculate the derivative
dx2d2y=dxd(−x)
Use differentiation rule dxd(cf(x))=c×dxd(f(x))
dx2d2y=−dxd(x)
Solution
dx2d2y=−1
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