Solve x^2 5x -5 - ScanMath

Question

Simplify the expression

5 x^{3} - 5

Evaluate

x^{2} \times 5 x - 5

Solution

More Steps

Evaluate

x^{2} \times 5 x

Multiply the terms with the same base by adding their exponents

x^{2 + 1} \times 5

Add the numbers

x^{3} \times 5

Use the commutative property to reorder the terms

5 x^{3}

5 x^{3} - 5

Show Solution

5 (x - 1) (x^{2} + x + 1)

Evaluate

x^{2} \times 5 x - 5

Evaluate

More Steps

Evaluate

x^{2} \times 5 x

Multiply the terms with the same base by adding their exponents

x^{2 + 1} \times 5

Add the numbers

x^{3} \times 5

Use the commutative property to reorder the terms

5 x^{3}

5 x^{3} - 5

Factor out 5 from the expression

5 (x^{3} - 1)

Solution

More Steps

Evaluate

x^{3} - 1

Rewrite the expression in exponential form

x^{3} - 1^{3}

Use a^{3} - b^{3} = (a - b) (a^{2} + ab + b^{2}) to factor the expression

(x - 1) (x^{2} + x \times 1 + 1^{2})

Any expression multiplied by 1 remains the same

(x - 1) (x^{2} + x + 1^{2})

1 raised to any power equals to 1

(x - 1) (x^{2} + x + 1)

5 (x - 1) (x^{2} + x + 1)

Show Solution

x = 1

Evaluate

x^{2} \times 5 x - 5

To find the roots of the expression,set the expression equal to 0

x^{2} \times 5 x - 5 = 0

Multiply

More Steps

Multiply the terms

x^{2} \times 5 x

Multiply the terms with the same base by adding their exponents

x^{2 + 1} \times 5

Add the numbers

x^{3} \times 5

Use the commutative property to reorder the terms

5 x^{3}

5 x^{3} - 5 = 0

Move the constant to the right-hand side and change its sign

5 x^{3} = 0 + 5

Removing 0 doesn't change the value,so remove it from the expression

5 x^{3} = 5

Divide both sides

\frac{5 x ^{3}}{5} = \frac{5}{5}

Divide the numbers

x^{3} = \frac{5}{5}

Divide the numbers

More Steps

Evaluate

\frac{5}{5}

Reduce the numbers

\frac{1}{1}

Calculate

1

x^{3} = 1

Take the 3 -th root on both sides of the equation

3 x^{3} = 31

Calculate

x = 31

Solution

x = 1

Show Solution