Question
Find the roots
x1=−1−3i,x2=−1+3i
Evaluate
x2+2x+10
To find the roots of the expression,set the expression equal to 0
x2+2x+10=0
Substitute a=1,b=2 and c=10 into the quadratic formula x=2a−b±b2−4ac
x=2−2±22−4×10
Simplify the expression
More Steps

Evaluate
22−4×10
Multiply the numbers
22−40
Evaluate the power
4−40
Subtract the numbers
−36
x=2−2±−36
Simplify the radical expression
More Steps

Evaluate
−36
Evaluate the power
36×−1
Evaluate the power
36×i
Evaluate the square root
More Steps

Evaluate
36
Write the number in exponential form with the base of 6
62
Reduce the index of the radical and exponent with 2
6
6i
x=2−2±6i
Separate the equation into 2 possible cases
x=2−2+6ix=2−2−6i
Simplify the expression
More Steps

Evaluate
x=2−2+6i
Divide the terms
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Evaluate
2−2+6i
Rewrite the expression
22(−1+3i)
Reduce the fraction
−1+3i
x=−1+3i
x=−1+3ix=2−2−6i
Simplify the expression
More Steps

Evaluate
x=2−2−6i
Divide the terms
More Steps

Evaluate
2−2−6i
Rewrite the expression
22(−1−3i)
Reduce the fraction
−1−3i
x=−1−3i
x=−1+3ix=−1−3i
Solution
x1=−1−3i,x2=−1+3i
Show Solution
